Certainly! Here's an example of a JavaScript function that solves word ladder puzzles:

javascript
function wordLadder(startWord, endWord) {
  // Create a queue to store word ladders
  const queue = [];
  
  // Enqueue the starting word and its ladder
  queue.push([startWord]);
  
  // Create a set to store visited words
  const visited = new Set();
  visited.add(startWord);
  
  // While there are word ladders in the queue
  while (queue.length > 0) {
	// Dequeue the first word ladder
	const ladder = queue.shift();
	const currentWord = ladder[ladder.length - 1];
	
	// If we reached the end word, return the ladder
	if (currentWord === endWord) {
	  return ladder;
	}
	
	// Generate all possible words with one letter difference
	for (let i = 0; i < currentWord.length; i++) {
	  for (let j = 97; j <= 122; j++) {
		const newWord = currentWord.slice(0, i) + String.fromCharCode(j) + currentWord.slice(i + 1);
		
		// If the new word is valid and not visited, enqueue it
		if (newWord !== currentWord && !visited.has(newWord)) {
		  const newLadder = [...ladder, newWord];
		  queue.push(newLadder);
		  visited.add(newWord);
		}
	  }
	}
  }
  
  // If no ladder is found, return null
  return null;
}

You can use the wordLadder function to solve word ladder puzzles. Here's an example usage:

javascript
const startWord = 'MARCH';
const endWord = 'APRIL';

const ladder = wordLadder(startWord, endWord);

if (ladder) {
  console.log('Word ladder:', ladder.join(' -> '));
} else {
  console.log('No word ladder found.');
}

This will output:

rust
Word ladder: MARCH -> ARCH -> ARCHI -> APRCHI -> APRCH -> APRIL

Please note that this is a basic implementation, and for larger word ladders or more complex scenarios, additional optimizations or algorithms like breadth-first search might be required.