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	<title>Comments on: Sums, differences, and surprises</title>
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	<link>http://bit-player.org/2006/sums-differences-and-surprises</link>
	<description>An amateur's outlook on computation and mathematics.</description>
	<pubDate>Fri, 30 Jul 2010 22:41:46 +0000</pubDate>
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		<title>By: Barry Cipra</title>
		<link>http://bit-player.org/2006/sums-differences-and-surprises#comment-888</link>
		<dc:creator>Barry Cipra</dc:creator>
		<pubDate>Sat, 26 Aug 2006 17:04:08 +0000</pubDate>
		<guid isPermaLink="false">http://bit-player.org/?p=61#comment-888</guid>
		<description>" ...I had generated the series by looking at differences of distinct elements, but it turns out that sums of not-necessarily-distinct elements yield the same series. Curious."

You say curious, I say obvious.  If a-b=c-d, then a+d=b+c.  Either all four are distinct, or else two are equal, say a=d.

My own decline is apparent in the assertion that {1,2,...,m-1} is the difference set for {0,1,2,...,m}.  I meant {1,2,...,m}.

As one randomly "grows" a set S from among the numbers 0 to m, the number of duplicates, either sum or difference, with each new number goes from none to all -- that is, when you add the n+1st number, you (usually) get no duplicates when n is small (compared to m) and nothing but duplicates when n is large.  In general you get some fraction, k/n.  I wonder what the transition looks like.</description>
		<content:encoded><![CDATA[<p>&#8221; &#8230;I had generated the series by looking at differences of distinct elements, but it turns out that sums of not-necessarily-distinct elements yield the same series. Curious.&#8221;</p>
<p>You say curious, I say obvious.  If a-b=c-d, then a+d=b+c.  Either all four are distinct, or else two are equal, say a=d.</p>
<p>My own decline is apparent in the assertion that {1,2,&#8230;,m-1} is the difference set for {0,1,2,&#8230;,m}.  I meant {1,2,&#8230;,m}.</p>
<p>As one randomly &#8220;grows&#8221; a set S from among the numbers 0 to m, the number of duplicates, either sum or difference, with each new number goes from none to all &#8212; that is, when you add the n+1st number, you (usually) get no duplicates when n is small (compared to m) and nothing but duplicates when n is large.  In general you get some fraction, k/n.  I wonder what the transition looks like.</p>
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